Quadruplet interaction¶
In Spirit, the quadruplet interaction term is written as
\[\mathcal{H}_{\rm quad}
=
- \sum_{ijkl} K_{ijkl} (\vec{n}_i \cdot \vec{n}_j)(\vec{n}_k \cdot \vec{n}_l)\]
First, notice that \(i \ne j\) and \(k \ne l\), otherwise the Hamiltonian is constant.
Second, a special case of this Hamiltonian have been discussed in one of the previous pages:
\(i = k\) and \(j = l\) (or equivalently \(i = l\) and \(j = k\))
This is a case of Biquadratic exchange.
In general the Hamiltonian maps to the \(\mathcal{H}_4\) term
\[\begin{split}\mathcal{H}_4
=
C_4
\sum_{\substack{\mu_1, \mu_2, \mu_3, \mu_4, \\ \alpha_1, \alpha_2, \alpha_3, \alpha_4, \\ i_1, i_2, i_3, i_4}}
V_{\mu_1, \mu_2, \mu_3, \mu_4; \alpha_1, \alpha_2, \alpha_3, \alpha_4}^{i_1, i_2, i_3, i_4}
\cdot
X_{\mu_1; \alpha_1}^{i_1}
\cdot
X_{\mu_2; \alpha_2}^{i_2}
\cdot
X_{\mu_3; \alpha_3}^{i_3}
\cdot
X_{\mu_4; \alpha_4}^{i_4}\end{split}\]
By expanding the dot product, one gets
\[\begin{split}\mathcal{H}_{\rm quad}^{\rm case \, 2}
=
- \sum_{\substack{\mu_1, \mu_2, \mu_3, \mu_4,\\ \alpha_1, \alpha_2, \alpha_3, \alpha_4, \\ i_1, i_2, i_3, i_4}}
K_{ijkl}^{i_1, i_2, i_3, i_4}
n_{i}^{i_1}
n_{j}^{i_2}
n_{k}^{i_3}
n_{l}^{i_4}\end{split}\]
where the tensor \(K_{ijkl}^{i_1, i_2, i_3, i_4}\) is defined as
\[\begin{split}K_{ijkl} &= K_{ijkl}^{xxxx} = K_{ijkl}^{yyyy} = K_{ijkl}^{zzzz} \\
&= K_{ijkl}^{xxyy} = K_{ijkl}^{xxzz} = K_{ijkl}^{yyzz} \\
&= K_{ijkl}^{yyxx} = K_{ijkl}^{zzxx} = K_{ijkl}^{zzyy} \\\end{split}\]
and all other components are zero. Then, one renames the indices as \(i \rightarrow (\mu_1, \alpha_1)\), \(j \rightarrow (\mu_2, \alpha_2)\), \(k \rightarrow (\mu_3, \alpha_3)\), \(l \rightarrow (\mu_4, \alpha_4)\) and correspondence becomes clear
\[\begin{split}C_4 &= -1 \\
V_{\mu_1, \mu_2, \mu_3, \mu_4; \alpha_1, \alpha_2, \alpha_3, \alpha_4}^{i_1, i_2, i_3, i_4}
&\leftrightarrow K_{ijkl}^{i_1, i_2, i_3, i_4}
\\
X_{\mu_1; \alpha_1}^{i_1} &\leftrightarrow n_{i}^{i_1} \\
X_{\mu_2; \alpha_2}^{i_2} &\leftrightarrow n_{j}^{i_2} \\
X_{\mu_3; \alpha_3}^{i_3} &\leftrightarrow n_{k}^{i_3} \\
X_{\mu_4; \alpha_4}^{i_4} &\leftrightarrow n_{l}^{i_4} \\\end{split}\]